Solveeit Logo

Question

Mathematics Question on Differential equations

The solution for the differential equation dyy+dxx=0{ \frac{dy}{y} +\frac{ dx}{x} = 0 } is

A

1y+1x=c{\frac{1}{y} + \frac{1}{x} = c }

B

logx.logy=c\log \, x . \log \, y = c

C

xy=cx \, y = c

D

x+y=cx + y = c

Answer

xy=cx \, y = c

Explanation

Solution

We have, dyy+dxx=0\frac{d y}{y}+\frac{d x}{x}=0
On integrating both sides, we get
logy+logx=logc\log\, y+\log \,x=\log \,c
logxy=logc\Rightarrow \log \,x y=\log \,c
xy=cx y=c