Question

The solubility product of silver iodide is 8.3 × 10–17 and the standard reduction potential of Ag, Ag+ electrode is + 0.8 volts at 25° C. The standard reduction potential of Ag,Agl/lÆ electrode from these data is

• A. – 0.30 V
• B.
  • 0.15 V
• C.
  • 0.10 V
• D. – 0.15 V

Answer 1

Answer: (D)

– 0.15 V

Answer 2

$E_{l - /Ag|Ag} = 0.8 - \frac{0.0591}{1}\log\frac{1}{K_{sp}}$= 0.8 + 0.0591 × log 8.3 × 10–17 = – 0.15 Volt or

}{= - 0.8 + 0.095 = 0.15V.}$$