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Question

Chemistry Question on Solutions

The solubility product of silver chromate is 4×10−124 \times 10^{-12}. The molar solubility of the salt is

A

1.0×10−4molL−11.0 \times 10^{-4} mol L^{-1}

B

2×10−10molL−12 \times 10^{-10} mol L^{-1} '

C

1.0×10−8molL−11.0 \times 10^{-8} mol L^{-1}

D

2×10−6molL−12 \times 10^{-6} mol L^{-1}

Answer

1.0×10−4molL−11.0 \times 10^{-4} mol L^{-1}

Explanation

Solution

Solubility =(Ksp/4)1/3 mol L−1=(K_{sp}/4)^{1/3}\,mol\,L^{-1}