Solveeit Logo
Login

Question

Question: The solubility of silver chromate in 0.01 M \(K_{2}CrO_{4}\) is \(2 \times 10^{- 8}moldm^{- 3}\). Th...

The solubility of silver chromate in 0.01 M K2CrO4K_{2}CrO_{4} is 2×10−8moldm−32 \times 10^{- 8}moldm^{- 3}. The solubility product of silver chromate will be.

A

8×10−248 \times 10^{- 24}

B

16×10−2416 \times 10^{- 24}

C

1.6×10−181.6 \times 10^{- 18}

D

16×10−1816 \times 10^{- 18}

Answer

16×10−1816 \times 10^{- 18}

Explanation

Solution

Ksp=[Ag+]2[Cro4−−]=[2S]2[0.01]K_{sp} = \lbrack Ag^{+}\rbrack^{2}\lbrack Cro_{4}^{- -}\rbrack = \lbrack 2S\rbrack^{2}\lbrack 0.01\rbrack

=4S2[0.01]=4[2×10−8]2×0.01=16×10−184S^{2}\lbrack 0.01\rbrack = 4\lbrack 2 \times 10^{- 8}\rbrack^{2} \times 0.01 = 16 \times 10^{- 18} .