Question
Question: The solubility of salt at \({30^ \circ }C\) is \(50.\) Calculate the weight of water required to pre...
The solubility of salt at 30∘C is 50. Calculate the weight of water required to prepare a saturated solution containing 90g of salt.
A. 90g
B. 180g
C. 100g
D. 50g
Solution
Solubility is a property referring to the ability of a given substance, the solute to dissolve in a solvent (In most of the cases the solvent is water). Solubility is measured in terms of the maximum amount of solute dissolve in a solvent at equilibrium.
Formula used: Solubilityofsolute(salt)=WsolventWsolute×100
Where, Wsolute is the weight of solute in saturated solution and Wsolvent is weight of solvent in saturated solution.
Complete step-by-step solution: In the given question it is given that the solubility of salt at 30∘C is 50. we have to determine the weight of water required to prepare a saturated solution containing 90g of salt.
Now, given weight of salt =90g
And solubility of salt =50
By using the above formula we can determine the weight of water.
Solubilityofsolute(salt)=WsolventWsolute×100
By putting the value of known quantity that is weight of salt and solubility, we get
50=Wsolvent90×100
On solving the above equation, we will get the value of the weight of water.
Wsolvent=5090×100
⇒ Wsolvent=180g
Therefore, 180g of water required to prepare a saturated solution containing 90g of salt.
So, the correct option is B.
Note: These are the parameters that affect the solubility of a solute in a solvent namely, temperature, and pressure.
Temperature: The solubility of a solute is directly proportional to the temperature that is higher the temperature of solvent the greater the solubility of the solute. There is an exception gaseous solute dissolve less in hotter liquid solvents than in colder solvents.
Pressure: Generally pressure does not affect the solubility of most solutes in a solvent but in the case gaseous solute dissolve more liquid solvents at higher pressures than at lower pressures.