Question

The solubility of $N_2$ in water at 300 K and 500 torr partial pressure is 0.01 g $L^{-1}$. The solubility (in g $L^{-1}$) at 750 torr partial pressure is :

• A. 0.0075
• B. 0.015
• C. 0.02
• D. 0.005

Answer 1

Answer: (B)

0.015

Answer 2

Partial Pressure = Mole fraction ? solubility
$\frac{p_{1}}{p_{2}}=\frac{s_{1}}{s_{2}} \Rightarrow \frac{500}{0.01}=\frac{750}{x}$
$\therefore x=0.015\,g / L$