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Question

Chemistry Question on Equilibrium

The solubility of Fe(OH)3Fe ( OH )_{3} is xmolL1x\, mol\, L ^{-1}. Its KspK_{s p} would be

A

9x3 9x^{3}

B

3x3 3x^{3}

C

27x4 27x^{4}

D

9x4 9x^{4}

Answer

27x4 27x^{4}

Explanation

Solution

Dissociation of Fe(OH)3Fe ( OH )_{3} in solution is represented as follows
Fe(OH)3(x)Fe3+(x)+3OH(3x)Ksp=x×(3x)3=27x4\underset{(-x)}{ Fe ( OH )_{3}} \rightleftharpoons \underset{(x)}{ Fe^{3+}} + \underset{(3x)}{3OH^-} K_{sp} = x \times (3x)^3 =27 x^{4}