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Question: The solubility of calcium phosphate in water is x mol h at 25 Degree C. Its solubility product is eq...

The solubility of calcium phosphate in water is x mol h at 25 Degree C. Its solubility product is equal to:
A. 108x2108{{x}^{2}}
B. 36x336{{x}^{3}}
C. 36x536{{x}^{5}}
D. 108x5108{{x}^{5}}

Explanation

Solution

All phosphates are insoluble aside from those of sodium, potassium and ammonium. Some hydrogen phosphates, for example, Ca3(PO4)2C{{a}_{3}}{{(P{{O}_{4}})}_{2}}, are solvent. I) All sulfides are insoluble aside from those of ammonium, sodium, calcium, potassium, magnesium, barium and strontium. These are somewhat hydrolyzed in water .

Step by step answer: The solubility product, by definition, is the equilibrium constant for dissolution of a solid ionic compound to yield ions in solution (usually water). It is abbreviated Ksp.
The equation for dissolution of calcium phosphateCa3(PO4)2C{{a}_{3}}{{(P{{O}_{4}})}_{2}} in water is:
Ca3(PO4)2C{{a}_{3}}{{(P{{O}_{4}})}_{2}}= 3Ca(2+)+2PO4(3)3Ca(2+)+2P{{O}_{4}}(3-)
and the equilibrium constant will be equal to:
Ksp = [Ca(2+)] ^3[PO4(3)] ^2\left[ Ca(2+) \right]\hat{\ }3*\left[ P{{O}_{4}}(3-) \right]\hat{\ }2
Now, if you want to solve problems like how much calcium phosphate will dissolve in water you need to replace [Ca(2+)]\left[ Ca{{(}^{2+}}) \right]and [PO4(3+)]\left[ P{{O}_{4}}{{(}^{3+}}) \right]with something more beneficial. For every mole ofCa3(PO4)2C{{a}_{3}}{{(P{{O}_{4}})}_{2}} when it dissolves, will yield 3 moles of (=3x) and 2 moles ofP{{O}_{4}}(3-)$$$$(=2x) so the Ksp expression becomes:
[Ca(2+)] ^3[PO4(3+)] ^2=>(3x) ^3(2x) ^2=108x ^5\left[ Ca{{(}^{2+}}) \right]\hat{\ }3*\left[ P{{O}_{4}}{{(}^{3+}}) \right]\hat{\ }2=>(3x)\hat{\ }3*(2x)\hat{\ }2=108x\hat{\ }5
Calcium phosphate is Ca3(PO4)2C{{a}_{3}}{{(P{{O}_{4}})}_{2}} ​.
Ca3(PO4)23Ca2++2PO43C{{a}_{3}}{{(P{{O}_{4}})}_{2}}3C{{a}^{2+}}+2P{{O}_{4}}^{3-}
3x3x 2x2x
Ksp=[3x]3[2x]2=108x5{{K}_{sp}}={{\left[ 3x \right]}^{3}}{{\left[ 2x \right]}^{2}}=108{{x}^{5}}

So, the correct option is D. 108x5108{{x}^{5}}

Additional Information: Elementary calcium reacts with water. Calcium compounds are more or less water soluble. Calcium carbonate has a solubility of, 14mg/L14mg/L which is multiplied by a factor five in presence of carbon dioxide. Calcium phosphate solubility is20mg/L20mg/L, and that of calcium fluoride is16mg/L16mg/L.

Note: At 25C{{25}^{\circ }}C and pH7.00pH7.00, Ksp for calcium phosphate is 2.0710332.07*{{10}^{-33}} , indicating that the concentrations of Ca2+C{{a}^{2+}} and Po43P{{o}_{4}}^{3-} ions in solution that are in equilibrium with solid calcium phosphate are very low.