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Chemistry Question on Solutions

The solubility of BaSO4BaSO_4 in water is 2.33×10−32.33 \times 10^{-3} gram/litre. Its solubility product will be (molecular weight of BaSO4=233BaSO_4 = 233)

A

1×10−151 \times 10^{-15}

B

1×10−101 \times 10^{-10}

C

1×10−51 \times 10^{-5}

D

1×10−201 \times 10^{-20}

Answer

1×10−101 \times 10^{-10}

Explanation

Solution

∴\therefore Solubility Product =[Ba2+][SO42−]=\left[ Ba ^{2+}\right]\left[ SO _{4}^{2-}\right] =s2=s^{2} =(10−5)2=\left(10^{-5}\right)^{2} =10−10=10^{-10}