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Question

Chemistry Question on Ionic Equilibrium In Solution

The solubility of AgCl will be minimum in

A

0.001MAgNO30.001\, M\, AgNO_3

B

purewaterpure\, water

C

0.01MCaCl20.01\, M\, CaCl_2

D

0.01 M NaCl

Answer

0.01MCaCl20.01\, M\, CaCl_2

Explanation

Solution

The solubility of insoluble substances can be decreased by the presence of a common ion. Present in silver chloride are silver ions (Ag+Ag^+ ) and chloride ions (Cl)Cl^-). AgClAgCl is not soluble in water. Silver nitrate (which is soluble) has silver ion in common with silver chloride. But the concentration of the common ion is low (0.001M) Calcium chloride (also soluble) has chloride ion in common with silver chloride. In CaCl2CaCl_2 has two moles of common ion (0.02M)(0.02\,M) that decreases solubility very rapidly. In Na2Na_2 SO4SO_4 there is no common ion effect apply therefore is soluble in it.