Question

The solubility in water of a sparingly soluble salt AB2 is 1.0 × 10–5mol L–1. Its solubility product will be :

• A. 4 × 10–15
• B. 4 × 10–10
• C. 1 × 10–15
• D. 1 × 10–10.

Answer 1

Answer: (A)

4 × 10–15

Answer 2

AB2 $\rightleftharpoons$ A2+ + 2B– s = 1.0 × 10–5 mol L–1

Ksp = [A2+] [B–]2 = 1.0 × 10–5 × (2.0 × 10–5)2 = 4.0 × 10–15