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Question: The smallest value of \(k\), for which both the roots of the equation \({{x}^{2}}-8kx+16\left( {{k}^...

The smallest value of kk, for which both the roots of the equation x28kx+16(k2k+1)=0{{x}^{2}}-8kx+16\left( {{k}^{2}}-k+1 \right)=0 are real, distinct and have values at least 44 is

Explanation

Solution

For this problem we need to calculate the value of kk such that the given equation x28kx+16(k2k+1)=0{{x}^{2}}-8kx+16\left( {{k}^{2}}-k+1 \right)=0 has real, distinct and have values at least 44. Here we have the two considerations: the first one is the roots of the given equation are real, distinct and the second consideration is the roots have at least 44. Now we will compare the given quadratic equation with the standard quadratic equation which is ax2+bx+c=0a{{x}^{2}}+bx+c=0 and write the values of aa, bb, cc. If we observe that the concept related to nature of the roots depends on the discriminant of the quadratic equation, so we will calculate the discriminant value of the quadratic equation which is b24ac{{b}^{2}}-4ac. We need to have a positive discriminant to have real and distinct roots. From this we can obtain an expression and solve the expression to get the range of the kk. Now we will consider the second part that the root has a value at least 44 . If the root has at least value of 44, then the value of f(4)f\left( 4 \right) should be greater than or equal to zero. From this also we can obtain an expression and solve for the range of kk. After getting ranges of kk, we can write the minimum value of kk.

Complete step by step solution:
Given the equation, x28kx+16(k2k+1)=0{{x}^{2}}-8kx+16\left( {{k}^{2}}-k+1 \right)=0.
Comparing the above given quadratic equation with the standard quadratic equation which is ax2+bx+c=0a{{x}^{2}}+bx+c=0, then the values of aa, bb, cc are
a=1a=1, b=8kb=-8k, c=16(k2k+1)c=16\left( {{k}^{2}}-k+1 \right).
The discriminant of the given quadratic equation will be
b24ac=(8k)24(1)[16(k2k+1)]{{b}^{2}}-4ac={{\left( -8k \right)}^{2}}-4\left( 1 \right)\left[ 16\left( {{k}^{2}}-k+1 \right) \right]
Simplifying the above equation by using the distribution law of multiplication and some other mathematical operations, then we will get
b24ac=64k264k2+64k64 b24ac=64k64 \begin{aligned} & {{b}^{2}}-4ac=64{{k}^{2}}-64{{k}^{2}}+64k-64 \\\ & \Rightarrow {{b}^{2}}-4ac=64k-64 \\\ \end{aligned}
If the given equation has a real, distinct roots then the discriminant of the given equation should be positive, we can write this mathematically as
b24ac>0{{b}^{2}}-4ac>0
Substituting the discriminant value that we have calculated, in the above equation, then we will get
64k64>064k-64>0
Divide the whole expression with 6464 on both sides, then we will get
k1>0k-1>0
Simplify the above expression by adding 11 on both sides, then we will have
k>1.....(i)\therefore k>1.....\left( \text{i} \right)
Now consider the point that the root has at least value of 44. That means the given equation should give a positive or zero value when we substitute 44 in the given equation. So, substituting 44 in the given equation, then we will get
f(4)=(4)28k(4)+16(k2k+1)f\left( 4 \right)={{\left( 4 \right)}^{2}}-8k\left( 4 \right)+16\left( {{k}^{2}}-k+1 \right)
Simplifying the above equation by using mathematical operation, then we will have
f(4)=1632k+16k216k+16 f(4)=16k248k+32 f(4)=16(k23k+2) \begin{aligned} & f\left( 4 \right)=16-32k+16{{k}^{2}}-16k+16 \\\ & \Rightarrow f\left( 4 \right)=16{{k}^{2}}-48k+32 \\\ & \Rightarrow f\left( 4 \right)=16\left( {{k}^{2}}-3k+2 \right) \\\ \end{aligned}
If the above value should be a positive or zero. It can be written as
f(4)0 16(k23k+2)0 \begin{aligned} & f\left( 4 \right)\ge 0 \\\ & \Rightarrow 16\left( {{k}^{2}}-3k+2 \right)\ge 0 \\\ \end{aligned}
Dividing the above equation with 1616 on both sides and splitting the middle term as 3k=k2k-3k=-k-2k and simplifying the expression by following some mathematical operations, then we will get
k2k2k+20 k(k1)2(k1)0 (k1)(k2)0 k1 or k2......(ii) \begin{aligned} & {{k}^{2}}-k-2k+2\ge 0 \\\ & \Rightarrow k\left( k-1 \right)-2\left( k-1 \right)\ge 0 \\\ & \Rightarrow \left( k-1 \right)\left( k-2 \right)\ge 0 \\\ & \Rightarrow k\ge 1\text{ or }k\ge 2......\left( \text{ii} \right) \\\ \end{aligned}
From equations (i)\left( \text{i} \right) and (ii)\left( \text{ii} \right) we can say the minimum value of the kk is 22.

Note: For this problem we can check for the value of kk by plotting the graph of the given equation for various kk values and observe whether the assumed kk values satisfy the given conditions or not. We can observe that for k=2k=2 the given equation satisfies the given conditions and the graphs will look like below.