Question

The smallest positive angle which satisfies the equation $\sin\theta = - \frac{3}{2}$, is.

• A. $\theta = \frac{\pi}{6},\pi - \frac{\pi}{6} = \frac{5\pi}{6}$
• B. $\cos\theta = - \frac{1}{\sqrt{2}} \Rightarrow \theta = \frac{3\pi}{4},\frac{5\pi}{4}$
• C. $\tan\theta = 1 \Rightarrow \theta = \frac{\pi}{4},\frac{5\pi}{4}$
• D. $\therefore$

Answer 1

Answer: (A)

$\theta = \frac{\pi}{6},\pi - \frac{\pi}{6} = \frac{5\pi}{6}$

Answer 2

$\tan\frac{\pi x}{4} = \frac{\pi}{\pi/4} = 4$

$\therefore f(x) =$

$\left| \sin\pi x \right| = \frac{\pi}{\pi} = 1.f(x) = \sin\left( \frac{\pi x}{n - 1} \right) + \cos\left( \frac{\pi x}{n} \right)$

$\Rightarrow$ $\cos\left( \frac{\pi x}{n} \right) = \frac{2\pi}{\left( \frac{\pi}{n} \right)} = 2n$.