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Chemistry Question on Classification of elements & periodicity in properties

The smallest among the following ion is:

A

Mg2+M{{g}^{2+}}

B

Na+N{{a}^{+}}

C

Ba2+B{{a}^{2+}}

D

Al3+A{{l}^{3+}}

Answer

Al3+A{{l}^{3+}}

Explanation

Solution

As we move from left to right in a period, the atomic size of elements decrease, hence among Na, Mg and Al, Al will be smallest. Further atomic size decrease with increase in oxidation number. Hence Al3+A{{l}^{3+}} ion is quite smaller than other three ions as it has maximum positive charge (+ 3).