Question

The small magnets each of magnetic moment 10 A-m² are placed end-on position 0.1m apart from their centres. The force acting between them is

• A.
• B. $0.06 \times 10 ^ { 7 } N$
• C.
• D.

Answer 1

Answer: (C)

Answer 2

$F = \frac { \mu _ { 0 } } { 4 \pi } \left( \frac { 6 M M ^ { \prime } } { d ^ { 4 } } \right)$ in end-on position between two small magnets.

$\therefore F = 10 ^ { - 7 } \left( \frac { 6 \times 10 \times 10 } { ( 0.1 ) ^ { 4 } } \right) = 0.6 \mathrm {~N}$