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Question

Mathematics Question on Hyperbola

The slope of the tangent to the hyperbola 2x23y2=62x^2 - 3y^2 = 6 at (3,2)(3, 2) is

A

-1

B

1

C

0

D

2

Answer

1

Explanation

Solution

Differentiating the given equation of the curve
4x6y.(dy/dx)=04 x-6 y .(d y / d x)= 0
dy/dx=2x/3y\therefore d y / d x=2 x / 3 y
(dydx)(3,2)=2332=1\left(\frac{d y}{d x}\right)_{(3,2)}=\frac{2}{3} \cdot \frac{3}{2}=1