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Question: The slope of the tangent to the curve y = \(\int_{0}^{x}\frac{dt}{1 + t^{3}}\) at the point where x...

The slope of the tangent to the curve y = 0xdt1+t3\int_{0}^{x}\frac{dt}{1 + t^{3}}

at the point where x = 1 is –

A

½

B

1

C

¼

D

None

Answer

½

Explanation

Solution

dydx=11+x3\frac{dy}{dx} = \frac{1}{1 + x^{3}}

put x = 1 Ž 12\frac{1}{2}