Question
Question: The slope of the tangent to the curve x = t<sup>2</sup> + 3t – 8, y = 2t<sup>2</sup>– 2t – 5 at the...
The slope of the tangent to the curve
x = t2 + 3t – 8, y = 2t2– 2t – 5 at the point (2, – 1) is –
A
22/7
B
6/7
C
– 6
D
None
Answer
6/7
Explanation
Solution
dxdy=dx/dtdy/dt=2t+34t−2
at x = 2 Ž 2 = t2 + 3t – 8 Ž t2 + 3t – 10 = 0
= –5, 2
at y = –1 Ž –1 = 2t2 – 2t – 5 Ž 2t2 – 2t – 4 = 0
Ž t = 2, – 1
\ put t = 2
\ dxdy=76