Question

The size of the nucleus of an atom of mass number $A$ is proportional to

• A. $A^{3/4}$
• B. $A^{2/3}$
• C. $A^{1/3}$
• D. $A^{5/3}$

Answer 1

Answer: (C)

$A^{1/3}$

Answer 2

Nuclear radius is proportional to $A^{1 / 3}$, where $A$ is the mass number of nucleus, ie, $R \propto A^{1 / 3}$. $\Rightarrow R=R_{0} A^{1 / 3}$. where $R_{0}=1.2 \times 10^{-15} m$