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Question: The size of image of O by M<sub>2</sub> is twice of image of O by M<sub>1</sub> and both images coin...

The size of image of O by M2 is twice of image of O by M1 and both images coincide. Find the distance of M1 form the pole of M2

A

30 cm

B

60 cm

C

45 cm

D

40 cm

Answer

45 cm

Explanation

Solution

m = 2 Ž u = 3f2\frac { 3 \mathrm { f } } { 2 } & M1 is in between O & its image so distance between then is = 3f2\frac { 3 \mathrm { f } } { 2 }+ 3f4\frac { 3 \mathrm { f } } { 4 }