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Question: The sin q and cosq are roots of the equation lx<sup>2</sup> + mx + n = 0, then...

The sin q and cosq are roots of the equation lx2 + mx + n = 0, then

A

l2 + m2 + 2ln = 0

B

l2 – m2 + 2ln = 0

C

l2 – m2 – 2ln = 0

D

None of these

Answer

l2 – m2 + 2ln = 0

Explanation

Solution

Here

sin q + cos q = –ml\frac{m}{\mathcal{l}} …(1)

sin q . cos q = nl\frac{n}{\mathcal{l}} …(2)

Squaring (1) (sin q + cos q)2 =m2l2\frac{m^{2}}{\mathcal{l}^{2}}

Ž sin2 q + cos2q + 2 sin q cos q =m2l2\frac{m^{2}}{\mathcal{l}^{2}}

Ž 1 + 2nl\frac{2n}{\mathcal{l}}=m2l2\frac{m^{2}}{\mathcal{l}^{2}}

Ž l2 + 2nl = m2

Ž l2 – m2 + 2nl = 0