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Question: The sin θ and cosθ are roots of the equation lx<sup>2</sup> + mx + n = 0, then...

The sin θ and cosθ are roots of the equation lx2 + mx + n = 0, then

A

l2 + m2 + 2ln = 0

B

l2 – m2 + 2ln = 0

C

l2 – m2 – 2ln = 0

D

None of these

Answer

l2 – m2 + 2ln = 0

Explanation

Solution

Here

sin θ + cos θ = –ml\frac{m}{\mathcal{l}} …(1)

sin θ . cos θ = nl\frac{n}{\mathcal{l}} …(2)

Squaring (1) (sin θ + cos θ)2 =m2l2\frac{m^{2}}{\mathcal{l}^{2}}

⇒ sin2 θ + cos2θ + 2 sin θ cos θ =m2l2\frac{m^{2}}{\mathcal{l}^{2}}

⇒ 1 + 2nl\frac{2n}{\mathcal{l}}=m2l2\frac{m^{2}}{\mathcal{l}^{2}}

⇒ l2 + 2nl = m2

⇒ l2 – m2 + 2nl = 0