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Question

Mathematics Question on Trigonometric Functions

The sides of a triangle are in the ratio 1:3:21 : \sqrt 3 : 2, then the angles of the triangle are in the ratio

A

1:03:05

B

2:03:02

C

3:02:01

D

1:02:03

Answer

1:02:03

Explanation

Solution

Let a : b : c = 1 : 3:2c2=a2+b2\sqrt 3 : 2 \Rightarrow c^2 = a^2 + b^2
\therefore Triangle is right angled at C
or C=90andab=13\angle C = 90^ \circ \, and \, \frac{a}{b} = \frac{1}{\sqrt 3}
In BAC,tanA=ab=13\triangle BAC, \, tan \, A = \frac{a}{b} = \frac{1}{\sqrt 3}
A=30andB=60\Rightarrow A = 30^ \circ \, and \, B = 60^\circ
\hspace29mm [A+B=90][ \because A + B = 90^\circ ]
\therefore Ratio of angles, A :B : C = 30:60:9030^\circ : 60^\circ : 90^\circ
= 1 : 2 : 3