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Question: The sides of a triangle are 3x + 4y, 4x + 3y and 5x + 5y units, where x, y \> 0. The triangle is...

The sides of a triangle are 3x + 4y, 4x + 3y and 5x + 5y units, where x, y > 0. The triangle is

A

Right angled

B

Equilateral

C

Obtuse angled

D

None of these

Answer

Obtuse angled

Explanation

Solution

Let a = 3x + 4y, b = 4x + 3y and C = 5x + 5y.

Clearly c is the largest side and then the largest angle C is given by

cos C = a2+b2c22ab\frac { a ^ { 2 } + b ^ { 2 } - c ^ { 2 } } { 2 a b }= 2xy2(12x2+25xy+12y2)<0\frac { - 2 x y } { 2 \left( 12 x ^ { 2 } + 25 x y + 12 y ^ { 2 } \right) } < 0.

⇒ C is an obtuse angle