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Question

Mathematics Question on Conic sections

The sides of a rectangle are given by x=±ax = \pm \, a and y=±by = \pm \, b. The equation of the circle passing through the vertices of the rectangle is

A

x2+y2=a2x^2 + y^2 = a^2

B

x2+y2=a2+b2x^2 + y^2 = a^2 + b^2

C

x2+y2=a2b2x^2 + y^2 = a^2 - b^2

D

(xa)2+(yb)2=a2+b2\left(x -a\right)^{2}+ \left(y-b\right)^{2} = a^{2} + b^{2}

Answer

x2+y2=a2+b2x^2 + y^2 = a^2 + b^2

Explanation

Solution

Given sides of rectangle are x=±ax=\pm a and y=±by=\pm b \therefore Centre of circle =(0,0)=(0,0) and radius of circle =a2+b2=\sqrt{a^{2}+b^{2}} \therefore Equation of circle x2+y2=(a2+b2)x^2 + y^2 = (a^2 + b^2)