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Question

Physics Question on Electric Current

The SI unit of the inductance, the henry can by written as

A

weber/ampere

B

volt-second/ampere

C

joule/( ampere)2)^2

D

ohm-second

Answer

ohm-second

Explanation

Solution

(a)L=ϕi (a) \, L = \frac{ \phi}{ i } or henry = weber ampere= \frac{\text{ weber} }{\text{ ampere} } (b) e = - L (didt) \bigg ( \frac{ di}{ dt} \bigg) L=e(di/dt)\therefore L = - \frac{ e}{ ( di / dt ) } or henry =volt - secondampere= \frac{ \text{volt - second}}{ \text{ampere}} (c) U = 12Li2L=2Ui2 \frac{1}{2} Li^2 \therefore L = \frac{ 2 U}{ i^2 } or henry = joule (ampere)2= \frac{\text{ joule}}{\text{ (ampere)}^2 } (d) U = 12Li2=i2Rt\frac{1}{2} Li^2 = i^2 R t \therefore L = Rt or henry = ohm-second