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Question: The SI unit of gravitational potential is : (A) \(Joule/kg\) (B) \(Joule^2 /kg\) (C) \(kg/J...

The SI unit of gravitational potential is :
(A) Joule/kgJoule/kg
(B) Joule2/kgJoule^2 /kg
(C) kg/Joulekg/Joule
(D) Joule/kg2Joule/kg^2

Explanation

Solution

Hint
The S.l. system of unit measurement is the international system of measurement of units. The SI unit of the measurement is accepted world-wide. The Sl system is formed to make the communication easy world-wide.

Complete step by step solution
The gravitational force of attraction between any two objects is:
Directly proportional to the product of masses and Inversely proportional to the square of distance between them. The gravitational force of attraction is given by,
F=Gm1m2r2F = \dfrac{{\mathop {Gm}\nolimits_1 \mathop m\nolimits_2 }}{{\mathop r\nolimits^2 }}
Where, G is the gravitational constant, m1\mathop m\nolimits_1 and m2\mathop m\nolimits_2 are the masses of the objects and r is the distance between the objects
We should know that gravitational potential is defined as the work done in bringing a unit mass from infinity to the point of interest. So gravitational potential is work done on a unit mass.
Gravitational Potential=Work DoneMassGravitational{\text{ }}Potential = \dfrac{{Work{\text{ }}Done}}{{Mass}}
(SI unit of Gravitational Potential) = (SI unit of Work Done)(SI unit Of Mass) \left( {SI{\text{ }}unit{\text{ }}of{\text{ }}Gravitational{\text{ }}Potential} \right){\text{ }} = {\text{ }}\dfrac{{\left( {SI{\text{ }}unit{\text{ }}of{\text{ }}Work{\text{ }}Done} \right)}}{{\left( {SI{\text{ }}unit{\text{ }}Of{\text{ }}Mass} \right)}}{\text{ }}
As we know that
SI unit of Work Done = JouleSI{\text{ }}unit{\text{ }}of{\text{ }}Work{\text{ }}Done{\text{ }} = {\text{ }}Joule
SI unit of mass = KgSI{\text{ }}unit{\text{ }}of{\text{ }}mass{\text{ }} = {\text{ }}Kg
Now put the SI units of Work Done and Mass in the gravitational Potential Equation-
SI unit of Gravitational Potential = JouleKg {\text{SI unit of Gravitational Potential }} = {\text{ }}\dfrac{{Joule}}{{Kg}}{\text{ }}
SI unit of Gravitational Potential = Joule/kg{\text{SI unit of Gravitational Potential }} = {\text{ Joule/kg}}
Thus option (A) is correct.

Note
The work required in bringing an object from infinity to a point in the presence of the gravitational field is known as the gravitational potential energy. It is represented by U that is U=mghU = mgh, where m is the mass, g is the acceleration due to the gravity, h is the height