Question

The shortest wavelength of the Brackett series of a hydrogen like atom (atomic number =Z) is the same as the shortest wavelength of the Balmar series of hydrogen atom. The value of Z is

• A. 2
• B. 3
• C. 4
• D. 5

Answer 1

Answer: (A)

2

Answer 2

$( Z^2) \left( \frac{13.6}{16} \right) = \left( \frac{13.6}{4} \right)$ $Z^2$ = 4 or Z = 2