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Quantitative Aptitude Question on Co-ordinate Geometry

The shortest distance of the point (12,1)(\frac{1}{2},1) from the curve y=∣x−1∣+∣x+1∣y = |x -1| + |x + 1| is

A

1

B

0

C

2\sqrt{2}

D

32\sqrt{\frac{3}{2}}

Answer

1

Explanation

Solution

shortest distance
The above illustration depicts the graph of y=∣x−1∣+∣x+1∣.y=∣x−1∣+∣x+1∣.
The shortest distance of (12,1)(\frac{1}{2},1)from the graph is 1