The shortest distance between the lines (\frac{x+7}{-6}=\fra... | Mathematics | SolveeIt

Question

The shortest distance between the lines $\frac{x+7}{-6}=\frac{y-6}{7}=z$ and $\frac{7-x}{2}=y-2=z-6$ is

$2 \sqrt{29}$

$\sqrt{\frac{37}{29}}$

$\frac{\sqrt{29}}{2}$

Answer

$2 \sqrt{29}$

Explanation

Solution

−6x+7=7y−6=1z−0:
point (−7,6,0) dr’s −6,7,1
2x−7=−1y−2=−1z−6:
point (7,2,6) dr’s 2,−1,−1
Shortest distance
=∣∣(−7+1)2+(6−2)2+(6−14)2∣∣14−62−47−161−1∣∣∣∣=229

Mathematics Question on Shortest Distance between Two Lines

Solution