Question

The shortest distance between the lines $\frac{x-2}{3}=\frac{y+1}{2}=\frac{z-6}{2}$ and $\frac{x-6}{3}=\frac{1-y}{2}=\frac{z+8}{0}$ is equal to

Answer 1

The correct answer is 14.
Shortest distance between the lines
=∣∣​i^33​j^​2−2​k^20​∣∣​∣∣​433​22−2​−1420​∣∣​​
=∣−4i^+6j^​−12k^∣16+12+168​=14196​=14