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Question

Question: The shortest distance between lines \(\frac{x - 3}{2} = \frac{y + 15}{- 7} = \frac{z - 9}{5}\) and\...

The shortest distance between lines

x32=y+157=z95\frac{x - 3}{2} = \frac{y + 15}{- 7} = \frac{z - 9}{5} andx+12=y11=z93\frac{x + 1}{2} = \frac{y - 1}{1} = \frac{z - 9}{- 3} is

A

232\sqrt{3}

B

434\sqrt{3}

C

363\sqrt{6}

D

565\sqrt{6}

Answer

434\sqrt{3}

Explanation

Solution

Use formula is cartesian form.