Question

The shape of $\left( \mathrm { CH } _ { 3 } \right) _ { 3 }$ N is pyramidal because

• A. Nitrogen forms three gybridised sigma bonds with carbon atoms of methyl groups and there is one non – bonding electron pair.
• B. Nitrogen form three hybridised sigma bonds with carbon atoms of methyl groups and fourth orbital forms pi bond
• C. Nitrogen has five valencies which are arranged in pyramidal shape.
• D. The unpaired electron present on nitrogen is delocalized.

Answer 1

Answer: (A)

Nitrogen forms three gybridised sigma bonds with carbon atoms of methyl groups and there is one non – bonding electron pair.

Answer 2

: Nitrogen forms three $\mathrm { sp } ^ { 3 }$ hybridized sigma bonds with carbon atoms of methyl group and has a non bonding electron pair in fourth orbital. Thus $\left( \mathrm { CH } _ { 3 } \right) _ { 3 } \mathrm {~N}$ has pyramidal shape.