Question

The set of real values of x for which $\log_{0.2} \frac{x +2}{x} \leq 1$ is

• A. $\bigg( - \infty , - \frac{5}{2} \bigg] \cup (0, \infty)$
• B. $\bigg[ \frac{5}{2} , \infty \bigg)$
• C. $( - \infty , -2) \cup [0 , \infty)$
• D. none of these

Answer 1

Answer: (A)

$\bigg( - \infty , - \frac{5}{2} \bigg] \cup (0, \infty)$

Answer 2

The inequality is ${log_{0.2} \frac{x + 2}{x} \leq 1}$ The L.H.S is valid if ${ \frac{x + 2}{x} > 0}$ $\Rightarrow \: {x(x + 2) > 0 \Rightarrow x < -2 \, or \: x > 0}$ Solving the inequality, we get (note that base < 1). ${ \frac{x + 2}{x}\geq 0.2 = \frac{1}{5}}$ $\Rightarrow \frac{x +2}{x} -\frac{1}{5} \ge 0 \Rightarrow \frac{4x + 10}{5x} \ge 0$ $x \left(2x+5\right)\ge0 \Rightarrow x \le -\frac{5}{2}$ or $x \ge0$ Taking the intersection, we get ${x \leq - \frac{5}{2}}$ or $x > 0$ $\Rightarrow \: x \in \left( - \infty , - \frac{5}{2} \right] \cup (0 , \infty)$