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Question: The set \(A = \left\{ x : x \in R , x ^ { 2 } = 16 \right.\) and \(2 x = 6 \}\) equals...

The set A={x:xR,x2=16A = \left\{ x : x \in R , x ^ { 2 } = 16 \right. and 2x=6}2 x = 6 \} equals

A

ϕ\phi

B

[14, 3, 4]

C

[3]

D

[4]

Answer

ϕ\phi

Explanation

Solution

x=±4x = \pm 4

x=3x = 3

There is no value of x which satisfies both the above equations. Thus, A=ϕA = \phi.