Question

The set A = \\{ x : x \in R, x^2 = 16 and 2x = 6\\} equals

• A. $\phi$
• B. $\\{ 14,3,4,\\}$
• C. $\\{3\\}$
• D. $\\{4\\}$

Answer 1

Answer: (A)

$\phi$

Answer 2

Since, $x^{2}=16$
$\Rightarrow x=\pm 4$
and $2 x=6$
$\Rightarrow x=3$
Hence, no value of $x$ is satisfied.
$\therefore A =\phi$