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Question: The separation between two microscopic particles is measured \(P_{A}\) and \(P_{B}\) by two differen...

The separation between two microscopic particles is measured PAP_{A} and PBP_{B} by two different lights of wavelength 2000 Å and 3000 Å respectively, then

A

PA>PBP_{A} > P_{B}

B

PA<PBP_{A} < P_{B}

C

PA<3/2PBP_{A} < 3/2P_{B}

D

PA=PBP_{A} = P_{B}

Answer

PA<PBP_{A} < P_{B}

Explanation

Solution

Resolving limit (minimum separation)∝λ\propto \lambda

⇒PAPB=20003000⇒PA<PB\Rightarrow \frac{P_{A}}{P_{B}} = \frac{2000}{3000} \Rightarrow P_{A} < P_{B}