Question
Physics Question on Keplers Laws
The semi-major axis of the orbit of Saturn is approximately nine times that of Earth. The time period of revolution of Saturn is approximately equal to
A
81 years
B
27 years
C
729 years
D
381 years
Answer
27 years
Explanation
Solution
Given, Semi-major axis of the orbit of saturn =grE Where, rE= semi major axis of earth According to Kepler's law, T2∝r3 Let the time period of revolution of saturn around the sun is Ts ∴TE2TS2=(rE9rE)3 TS2=TE2(9)3 TS=TE2(9)3 =93/2×1 year ≈27 years