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Question: The self inductance of a coil is 5 henry, a current of 1 amp change to 2 amp within 5 second through...

The self inductance of a coil is 5 henry, a current of 1 amp change to 2 amp within 5 second through the coil. The value of induced e.m.f. will be

A

10 volt

B

0.10 volt

C

1.0 volt

D

100 volt

Answer

1.0 volt

Explanation

Solution

e=Ldidte=5×15=16muvolte = - L\frac{di}{dt} \Rightarrow e = 5 \times \frac{1}{5} = 1\mspace{6mu} volt