Question
Question: The self-inductance of a choke coil is \(10{\text{ }}mH.\)When it is connected with a \(10{\text{ }}...
The self-inductance of a choke coil is 10 mH.When it is connected with a 10 VDC source, then the loss of power is 20W. When it is connected with 10V AC source loss of power is 10W. The frequency of AC source will be-
(A) 80Hz
(B) 100Hz
(C) 120Hz
(D) 220Hz
Solution
Hint
Self-inductance is defined as the property of an electric conductor to oppose the change in the electric current flowing in the conductor. It is usually represented by L. Whenever the current in the coil changes the E.M.F is induced in the circuit. Its S.I unit is usually taken as Henry. Power is defined as the rate of doing work.
Complete step by step solution
In DC power loss is only due to resistance we can write
Power loss in DC = RV2
Where V is voltage and R is resistance,
Putting the value-
R=PV2
R=20102=20100=5Ω
Now power loss in AC = Z2Vrms2×R
Where Z is impedance.
Putting the values -
Z2=PVrms2×R
=1010×10×5=50
Now, Z2=50
Z=50
Z=R+XL (where XL is reactance)
Squaring both sides
50=25+XL2
XL2=25
XL=5
XL=ωL=2πf×L ( where f is frequency )
5=2πf×10×10−3f
= 80Hz.
Option (A) is the correct option.
Note
Impedance is usually defined as the opposition to the current in the electric circuit. It is equal to the sum of resistance and reactance. Reactance is the non – resistive component of impedance. Impedance is represented by Z.Z=R+XL ( where XLis reactance and R is resistance).