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Question

Physics Question on Electromagnetic waves

The self induced emf of a coil is 2525 volts. When the current in it is changed at uniform rate from 10A10\, A to 25A25\, A in 1s1s, the change in the energy of the inductance is :

A

437.5 J

B

637.5 J

C

740 J

D

540 J

Answer

437.5 J

Explanation

Solution

Ldidt=25L \frac{di}{dt} =25 L×151=25L\times\frac{15}{1} =25 L=53H L= \frac{5}{3}H ΔE=12×53×(252102)=56×525=437.5J\Delta E = \frac{1}{2} \times\frac{5}{3}\times\left(25^{2} - 10^{2}\right) = \frac{5}{6} \times525 = 437.5\, J