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Question: The Schrodinger wave equation for hydrogen atom is: \[{{\Psi }_{2s}}=\dfrac{1}{4\sqrt{2}\pi }{{\le...

The Schrodinger wave equation for hydrogen atom is:
Ψ2s=142π(1a0)3/2[2r0a0]er/a0{{\Psi }_{2s}}=\dfrac{1}{4\sqrt{2}\pi }{{\left( \dfrac{1}{{{a}_{0}}} \right)}^{3/2}}\left[ 2-\dfrac{{{r}_{0}}}{{{a}_{0}}} \right]{{e}^{-r/{{a}_{0}}}}
where, a0{{a}_{0}} is Bohr radius. If the radial node in 2s2s be at r0{{r}_{0}}, then find rr in terms of a0{{a}_{0}}.
A.a02\dfrac{{{a}_{0}}}{2}
B.2a02{{a}_{0}}
C.2a0\sqrt{2}{{a}_{0}}
D.a02\dfrac{{{a}_{0}}}{\sqrt{2}}

Explanation

Solution

Bohr radius is the distance between the nucleus and electron of an atom. The probability of an electron located at a particular point is given by the square value of the wave function. In this equation, r0{{r}_{0}} is the radial node.

Complete step by step answer:
Here, it is given that the Schrodinger wave equation for hydrogen atom is:
Ψ2s=142π(1a0)3/2[2r0a0]er/a0{{\Psi }_{2s}}=\dfrac{1}{4\sqrt{2}\pi }{{\left( \dfrac{1}{{{a}_{0}}} \right)}^{3/2}}\left[ 2-\dfrac{{{r}_{0}}}{{{a}_{0}}} \right]{{e}^{-r/{{a}_{0}}}}
where, a0{{a}_{0}} is Bohr radius, r0{{r}_{0}} is the radial node and Ψ\Psi is the wave function.
When wave function passes through zero, a node occurs. The electron has zero probability of being located at a node. The probability of an electron located at a particular point is given by the square value of the wave function. As we discussed that electron has zero probability of being located at a node, we can say that
Ψ2s2=0|{{\Psi }_{2s}}{{|}^{2}}=0
Now, looking at the above equation, we can observe that, if the square of the value of wave function is equal to zero, then the value of (2a0r0)\left( 2-\dfrac{{{a}_{0}}}{{{r}_{0}}} \right) has to be equal to zero.
Since, 142π\dfrac{1}{4\sqrt{2}\pi } is a constant which cannot be equal to zero and the value of (1a0)3/2{{\left( \dfrac{1}{{{a}_{0}}} \right)}^{3/2}} and er/a0{{e}^{-r/{{a}_{0}}}} will always be greater than zero.
So, therefore, we can write
2r0a0=02-\dfrac{{{r}_{0}}}{{{a}_{0}}}=0
On further simplifying, we get,
r0=2a0\Rightarrow {{r}_{0}}=2{{a}_{0}}

Therefore, the correct option is (B) 2a02{{a}_{0}}.

Additional information:
-Schrodinger wave equation is an equation that is used to calculate the wave function of a quantum – mechanical system. The wave function is used to define the state of the system at each spatial position and time.
-Wave function is defined as the quantum state of an isolated quantum system. It is denoted with a symbol, Ψ\Psi

Note: A wave function node generally occurs at a point where wave function is zero, that means, the electron has zero probability of being located at a node.
-Bohr radius is the most probable distance between the electron and the nucleus.