Question
Question: The Schrodinger wave equation for hydrogen atom is: \[{\Psi _{2s}} = \dfrac{1}{{4\sqrt 2 }}{\le...
The Schrodinger wave equation for hydrogen atom is:
Ψ2s=421(a01)23[2−a0r0]e−a0r
Where a0 is Bohr radius. If the radial node in 2s be at r0 , then find r in terms of a0
A.2a0
B.2a0
C.2a0
D.2a0
Solution
The radial node occurs where the radial component Rnl(r) of the wave function goes to zero, therefore Ψ2s2=0 and At node, the radial node is at r0 , So [2−a0r0] = 0, then we can calculate r in terms of a0
Complete step by step answer:
Given in the question,
The Schrodinger wave equation for hydrogen atom is
Ψ2s=421(a01)23[2−a0r0]e−a0r
The radial node occurs where the radial component Rnl(r) of the wave function goes to zero. Ψ2s2=0 since there is no angular component YIml(θ,∅) to a wave function for a spherical orbital (l=0,ml=0)
At node, the radial node is at r0
0 = [2−a0r0]e−a0r
Since e−a0r=0 for r in between 0 and ∞ (where nodes can occur), that can be divided out as well.
∴2−a0r0=0
a0r0=2
r0=2a0
Therefore, the correct answer is option (B).
Note: The wave function (Ψ) , is a mathematical function which is used to describe a quantum object. The wave function that describes an electron in an atom is a product between the radial wave function and the angular wave function. The radial wave function depends only on the distance from the nucleus and is represented by r.
A node occurs when a wave function changes signs, i.e. when its passes through zero. And a radial node occurs when a radial wave function passes through zero. An electron has the zero probability of being located at a node.