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Question

Physics Question on momentum

The satellite of mass m revolving in a circular orbit of radius r around the earth has kinetic energy E. Then its angular momentum will be

A

Emr2\sqrt{\frac{E}{mr^2}}

B

E2mr2\frac{E}{2 mr^2}

C

2Emr2\sqrt{2 E mr^2}

D

2Emr\sqrt{2 E mr}

Answer

2Emr2\sqrt{2 E mr^2}

Explanation

Solution

KE of a satellite E=12mv2E = \frac{1}{2} mv^2 or mv=2Emmv = \sqrt{2 E m} Angular momentum L=mvr=(2Em)×r L = m v r = (\sqrt{2E m}) \times r =2mEr2 = \sqrt{2 m E r^2}