Solveeit Logo

Question

Question: The S.I. unit of radioactivity is A. Becquerel B. Curie C. Rutherford D. Roentgen...

The S.I. unit of radioactivity is
A. Becquerel
B. Curie
C. Rutherford
D. Roentgen

Explanation

Solution

When an unstable nucleus undergoes a decay, the process is known by the phenomenon of radioactivity. It is also called radioactive decay. Here, we need to know about units of radioactivity and then we will identify the S.I. unit of radioactivity.

Complete answer:
It is interesting that except the last option, all three options are the units of radioactivity.
The last option, Roentgen is the unit for measuring the ionized radiation.
Now, we will define all the three remaining units.
First is Becquerel. It is defined as a quantity of radioactive material where one disintegration occurs per second. This unit is named after the discoverer of radioactivity, Henry Becquerel.
The second option is Curie. It can be defined as the quantity of any radioactive material in which the number of decays per second is 3.7×10103.7 \times {10^{10}} . The name Curie has been taken from Pierre and Marie Curie. Sometimes it is also used as smaller units such as millicurie and microcurie.
The third option is Rutherford. This unit can be defined as the quantity of the radioactive material where one million decays take place per second. This unit is named after a physicist Ernest Rutherford who classified radiation into alpha, beta, and gamma types and discovered the atomic nucleus.
From these three units, the S.I, unit of radioactivity is Becquerel.

So, the correct answer is “Option A”.

Note:
Let us see the values of all these three units of radioactivity
1Curie=1Ci=3.7×1010dps=3.7×1010Becquerel1Curie = 1Ci = 3.7 \times {10^{10}}dps = 3.7 \times {10^{10}}Becquerel
1Becquerel=1dps=2.703×1011Curie1Becquerel = 1dps = 2.703 \times {10^{ - 11}}Curie (This is S.I. unit of radioactivity)
1Rutherford=106dps1Rutherford = {10^6}dps
Here, dpsdps means decays per second.