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Question

Physics Question on Moment Of Inertia

The rotational kinetic energy of a body is KEKE and its moment of inertia is II The angular momentum is

A

KEIKEI

B

2KEI2\sqrt{KEI}

C

2KEI\sqrt{2KEI}

D

KE/IKE/I

Answer

2KEI\sqrt{2KEI}

Explanation

Solution

Rotational, KE=12Iω2K E=\frac{1}{2} I \omega^{2} \ldots (i) Angular momentum (L)=Iω(L)=I \omega or L2=I2ω2L^{2}=I^{2} \omega^{2} \ldots (ii) KEL2=12Iω2I2ω2=12I\therefore \frac{K E}{L^{2}}=\frac{\frac{1}{2} I \omega^{2}}{I^{2} \omega^{2}}=\frac{1}{2 I} L2=2KEIL^{2}=2 K E I L=2KEIL=\sqrt{2 K E I}