The roots of the equation (x^{2} + kx - 24 = 0,) are. | MATH - SOLUTION OF QUADRATIC EQUATIONS AND NATURE OF ROOTS | SolveeIt

The roots of the equation $x^{2} + kx - 24 = 0,$ are.

$x^{2} - 5x + k = 0$

$x^{2} - kx + 6 = 0$

$x^{2} + kx + 24 = 0$

$\alpha \neq \beta$

Answer

$x^{2} + kx + 24 = 0$

Explanation

We have $- p + q + r$

⇒ $ax^{2} + bx + c = 0$ ⇒ $bx^{2} + cx + a = 0$

⇒ $a \neq 0$ ⇒ $\frac{a^{3} + b^{3} + c^{3}}{abc} =$ .

Question: The roots of the equation \(x^{2} + kx - 24 = 0,\) are....