Question

The roots of the equation $\alpha^{2} = 5\alpha - 3$ are.

• A. 1, 4
• B. $\alpha/\beta$
• C. $\beta/\alpha$
• D. 1, 8

Answer 1

Answer: (C)

$\beta/\alpha$

Answer 2

$x^{2} + px + q = 0$⇒ $x^{2} + qx + p = 0$

Let$p + q + 1 =$ then $x^{2} + ax + 10 = 0$⇒ $x^{2} + bx - 10 = 0$

Hence $a^{2} - b^{2}$ (by $x^{2} - 11x + a$).