The roots of the equation (7x^{2} - 16x + 8 = 0) are. | MATH - SOLUTION OF QUADRATIC EQUATIONS AND NATURE OF ROOTS | SolveeIt

The roots of the equation $7x^{2} - 16x + 8 = 0$ are.

$1 - i$

$x^{2} - ax + b = 0$

$b =$

None of these

Answer

$x^{2} - ax + b = 0$

Explanation

Equation $x^{2} + rx + pq = 0$

⇒ $\frac{- (p + q + r)}{2}$ ⇒ $\frac{- p + q + r}{2}$

⇒ $- (p + q + r)$ .

Question: The roots of the equation \(7x^{2} - 16x + 8 = 0\) are....