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Chemistry Question on States of matter

The root means square velocity of hydrogen at STPSTP is 1.83×105 cm sec−11.83 \times 10^5 \,cm \, sec^{-1} and its means free path is 1.78×10−5 cm1.78 \times 10^{-5} \,cm . What will be the collision number at STPSTP ?

A

9.476×109 sec−19.476 \times 10^9\,sec^{-1}

B

9.746×10−9 sec−19.746 \times 10^{-9}\,sec^{-1}

C

9.746×109 sec−19.746 \times 10^9\,sec^{-1}

D

9.647×10−9 sec−19.647 \times 10^{-9}\,sec^{-1}

Answer

9.476×109 sec−19.476 \times 10^9\,sec^{-1}

Explanation

Solution

Z=VrmsλZ = \frac{V_{rms}}{\lambda} =1.83×1051.783×10−5 = \frac{1.83 \times 10^5}{1.783 \times 10^{-5}} =1.026×1010 = 1.026 \times 10^{10} =9.476×109 sec−1 = 9.476 \times 10^9 \,sec^{-1}